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4x^2+14x+3.25=0
a = 4; b = 14; c = +3.25;
Δ = b2-4ac
Δ = 142-4·4·3.25
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-12}{2*4}=\frac{-26}{8} =-3+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+12}{2*4}=\frac{-2}{8} =-1/4 $
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